The pipe is closed at the other end. If the pipe is the shortest possible 'closed’ pipe in which thesound will resonate, the time taken for the sound to travel down and back up the pipe is
Question
The pipe is closed at the other end. If the pipe is the shortest possible 'closed’ pipe in which thesound will resonate, the time taken for the sound to travel down and back up the pipe is
Solution
The time taken for sound to travel down and back up a pipe is determined by the speed of sound and the length of the pipe. In a closed pipe, the shortest possible length that will resonate is half the wavelength of the sound.
Step 1: Determine the wavelength of the sound. This can be calculated using the formula: wavelength = speed of sound / frequency.
Step 2: Since the shortest resonating closed pipe is half a wavelength, divide the wavelength by 2 to get the length of the pipe.
Step 3: Calculate the time taken for sound to travel down and back up the pipe. This can be calculated using the formula: time = 2 * length of pipe / speed of sound.
Remember, the speed of sound varies depending on the medium (it's faster in solids than in liquids, and faster in liquids than in gases), and the temperature and pressure of the medium.
Similar Questions
If the air temperature decreases, how does the resonant frequency in a pipe closed at one end change?Select one:a.It decreases.b.It doesn't change because resonance is pressure phenomenon.c.It doesn't change since one end of the pipe is closed.d.It increases.
A pipe, closed at one end, has a loudspeaker at the open end. For some frequencies of soundfrom the loudspeaker, a stationary sound wave is formed in the air within the pipe with anantinode at the open end of the pipe.0.85 mloudspeaker pipeThe length of the pipe is 0.85 m.The speed of sound in air is 340 m s –1.Which frequency of sound from the loudspeaker would not produce a stationary wave?A 100 Hz B 200 Hz C 300 Hz D 500 Hz
By considering your diagrams from part (b) or otherwise, show that the frequency of the nth harmonic of a tube of length L that is open at one end and closed at the other end is given by 𝑓𝑛 = 𝑛 ( 𝑣 4𝐿 ) where v is the speed of sound in air
Difference between the resonance lengths of two successive overtones of a tube closed at one end was 32 cm.If the end correction of the tube is 0.5 cm, what is the resonance length of the pipe when it vibrates at it’sfundamental frequency?
The fundamental frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. If length of the open pipe is 60 cm, the length of the closed pipe will be :
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.