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Find all the critical numbers of y equals x to the power of 4 minus 2 x squared minus 3, then determine the local minimum and maximum points by using a graph. Critical numbers: x equals short dash 1, x equals 0, and x equals 1 left parenthesis short dash 1 comma short dash 4 right parenthesis and left parenthesis 1 comma short dash 4 right parenthesis are local minimums and left parenthesis 0 comma short dash 3 right parenthesis is a local maximum. Critical numbers: x equals short dash 1 and x equals 1 left parenthesis short dash 1 comma short dash 4 right parenthesis and left parenthesis 1 comma short dash 4 right parenthesis are local minimums. Critical numbers: x equals 0 and x equals short dash 1 left parenthesis short dash 1 comma short dash 4 right parenthesis is a local and global minimum and left parenthesis 0 comma short dash 3 right parenthesis is a local maximum. Critical numbers: x equals 0 and x equals 1 left parenthesis 1 comma short dash 4 right parenthesis is a local minimum and left parenthesis 0 comma short dash 3 right parenthesis is a local maximum.

Question

Find all the critical numbers of y equals x to the power of 4 minus 2 x squared minus 3, then determine the local minimum and maximum points by using a graph.

Critical numbers: x equals short dash 1, x equals 0, and x equals 1

left parenthesis short dash 1 comma short dash 4 right parenthesis and left parenthesis 1 comma short dash 4 right parenthesis are local minimums and left parenthesis 0 comma short dash 3 right parenthesis is a local maximum.

Critical numbers: x equals short dash 1 and x equals 1

left parenthesis short dash 1 comma short dash 4 right parenthesis and left parenthesis 1 comma short dash 4 right parenthesis are local minimums.

Critical numbers: x equals 0 and x equals short dash 1

left parenthesis short dash 1 comma short dash 4 right parenthesis is a local and global minimum and left parenthesis 0 comma short dash 3 right parenthesis is a local maximum.

Critical numbers: x equals 0 and x equals 1

left parenthesis 1 comma short dash 4 right parenthesis is a local minimum and left parenthesis 0 comma short dash 3 right parenthesis is a local maximum.

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Solution

First, we need to find the derivative of the function y = x^4 - 2x^2 - 3. The derivative is y' = 4x^3 - 4x.

Next, we set the derivative equal to zero to find the critical numbers. Solving the equation 4x^3 - 4x = 0 gives us x = -1, 0, and 1.

Now, we need to determine whether these critical numbers correspond to local minimums, local maximums, or neither. We can do this by examining the sign of the derivative on either side of each critical number.

For x = -1, the derivative is positive to the left and negative to the right, so this is a local maximum.

For x = 0, the derivative is negative to the left and positive to the right, so this is a local minimum.

For x = 1, the derivative is positive to the left and negative to the right, so this is a local maximum.

So, the local minimum is at (0, -3) and the local maximums are at (-1, -4) and (1, -4).

This problem has been solved

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