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If 127.8 J of heat is added to a 4.0 gram sample of iron metal and the temperature of the metal increases from 25°C to 97°C, what is the specific heat of iron?A 0.0044 J/g°CB 0.044 J/g°CC 0.444 J/g°CD 4.4 J/g°C

Question

If 127.8 J of heat is added to a 4.0 gram sample of iron metal and the temperature of the metal increases from 25°C to 97°C, what is the specific heat of iron?A 0.0044 J/g°CB 0.044 J/g°CC 0.444 J/g°CD 4.4 J/g°C

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Solution

The specific heat of a substance can be calculated using the formula:

q = mcΔT

where: q = heat energy absorbed or released (in joules) m = mass of the substance (in grams) c = specific heat (in J/g°C) ΔT = change in temperature (in °C)

In this case, we are given: q = 127.8 J m = 4.0 g ΔT = 97°C - 25°C = 72°C

We are asked to find the specific heat (c), so we rearrange the formula to solve for c:

c = q / (m * ΔT)

Substituting the given values:

c = 127.8 J / (4.0 g * 72°C) = 0.444 J/g°C

So, the specific heat of iron is 0.444 J/g°C, which corresponds to option C.

This problem has been solved

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