Sure, let's solve this step by step:

1. First, we need to calculate the depression in freezing point which is the difference between the normal freezing point and the freezing point of the solution. The normal freezing point of water is 273.15 K. So, the depression in freezing point, ΔTf = 273.15 K - 270.67 K = 2.48 K.

2. The formula for calculating the depression in freezing point is ΔTf = Kf * m, where m is the molality of the solution and Kf is the cryoscopic constant of water. We can rearrange this formula to solve for molality: m = ΔTf / Kf = 2.48 K / 1.86 K kg mol^-1 = 1.333 mol/kg.

3. Molality is also defined as the number of moles of solute per kilogram of solvent. So, we can set up the equation 1.333 mol/kg = n / 0.250 kg, where n is the number of moles of solute and 0.250 kg is the mass of the solvent (water) in kilograms. Solving for n gives n = 1.333 mol/kg * 0.250 kg = 0.333 mol.

4. The molar mass of the solute is defined as the mass of the solute divided by the number of moles of solute. So, the molar mass = 60 g / 0.333 mol = 180 g/mol.

So, the molar mass of the solute is 180 g/mol.

Question

Sure, let's solve this step by step:

1. First, we need to calculate the depression in freezing point which is the difference between the normal freezing point and the freezing point of the solution. The normal freezing point of water is 273.15 K. So, the depression in freezing point, ΔTf = 273.15 K - 270.67 K = 2.48 K.

2. The formula for calculating the depression in freezing point is ΔTf = Kf * m, where m is the molality of the solution and Kf is the cryoscopic constant of water. We can rearrange this formula to solve for molality: m = ΔTf / Kf = 2.48 K / 1.86 K kg mol^-1 = 1.333 mol/kg.

3. Molality is also defined as the number of moles of solute per kilogram of solvent. So, we can set up the equation 1.333 mol/kg = n / 0.250 kg, where n is the number of moles of solute and 0.250 kg is the mass of the solvent (water) in kilograms. Solving for n gives n = 1.333 mol/kg * 0.250 kg = 0.333 mol.

4. The molar mass of the solute is defined as the mass of the solute divided by the number of moles of solute. So, the molar mass = 60 g / 0.333 mol = 180 g/mol.

So, the molar mass of the solute is 180 g/mol.

Knowee AI · Accepted Answer

Sure, let's solve this step by step:

1. First, we need to calculate the depression in freezing point which is the difference between the normal freezing point and the freezing point of the solution. The normal freezing point of water is 273.15 K. So, the depression in freezing point, ΔTf = 273.15 K - 270.67 K = 2.48 K.

2. The formula for calculating the depression in freezing point is ΔTf = Kf * m, where m is the molality of the solution and Kf is the cryoscopic constant of water. We can rearrange this formula to solve for molality: m = ΔTf / Kf = 2.48 K / 1.86 K kg mol^-1 = 1.333 mol/kg.

3. Molality is also defined as the number of moles of solute per kilogram of solvent. So, we can set up the equation 1.333 mol/kg = n / 0.250 kg, where n is the number of moles of solute and 0.250 kg is the mass of the solvent (water) in kilograms. Solving for n gives n = 1.333 mol/kg * 0.250 kg = 0.333 mol.

4. The molar mass of the solute is defined as the mass of the solute divided by the number of moles of solute. So, the molar mass = 60 g / 0.333 mol = 180 g/mol.

So, the molar mass of the solute is 180 g/mol.

A solution containing 60 g of a non-volatile solute in 250 g of water freezes at 270.67 K. Calculate the molar mass of the solute. (Kf of water = 1.86 K kg mol).

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