A wire carrying a 3 A current is placed in a 2 T magnetic field. If the length of the wire in the field is 1.5 m and the wire is perpendicular to the field, what is the force on the wire?a.12 Nb.3 Nc.6 Nd.9 N
Question
A wire carrying a 3 A current is placed in a 2 T magnetic field. If the length of the wire in the field is 1.5 m and the wire is perpendicular to the field, what is the force on the wire?a.12 Nb.3 Nc.6 Nd.9 N
Solution
The force on a current-carrying wire placed in a magnetic field is given by the formula:
F = BIL
where: F is the force, B is the magnetic field strength, I is the current, and L is the length of the wire.
Given: B = 2 T, I = 3 A, and L = 1.5 m,
we can substitute these values into the formula:
F = (2 T)(3 A)(1.5 m) = 9 N.
So, the force on the wire is 9 N. The correct answer is d. 9 N.
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