When a probabilistic bit is in (10)(10) , we apply the operator (1/21/201)(1/201/21) three times. What is the probability of being in state ⌈1⌋⌈1⌋ at the end?Group of answer choices3/41/87/81/21/4
Question
When a probabilistic bit is in (10)(10) , we apply the operator (1/21/201)(1/201/21) three times. What is the probability of being in state ⌈1⌋⌈1⌋ at the end?Group of answer choices3/41/87/81/21/4
Solution
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We apply a controlled-NOT operator on two probabilistic bits where the second one is the controlled bit and the first one is the target bit.Which of the following matrix represent this operator?Group of answer choices⎛⎝⎜⎜⎜⎜1000010000100001⎞⎠⎟⎟⎟⎟(1000010000100001) ⎛⎝⎜⎜⎜⎜1000010000010010⎞⎠⎟⎟⎟⎟(1000010000010010) ⎛⎝⎜⎜⎜⎜0001001001001000⎞⎠⎟⎟⎟⎟(0001001001001000) ⎛⎝⎜⎜⎜⎜1000000100100100⎞⎠⎟⎟⎟⎟(1000000100100100) ⎛⎝⎜⎜⎜⎜1000001001000001⎞⎠⎟⎟⎟⎟(1000001001000001) PreviousNext
We apply a controlled-NOT operator on two probabilistic bits where the second one is the controlled bit and the first one is the target bit.Which of the following matrix represent this operator?Group of answer choices⎛⎝⎜⎜⎜⎜1000010000010010⎞⎠⎟⎟⎟⎟(1000010000010010) ⎛⎝⎜⎜⎜⎜0001001001001000⎞⎠⎟⎟⎟⎟(0001001001001000) ⎛⎝⎜⎜⎜⎜1000001001000001⎞⎠⎟⎟⎟⎟(1000001001000001) ⎛⎝⎜⎜⎜⎜1000000100100100⎞⎠⎟⎟⎟⎟(1000000100100100) ⎛⎝⎜⎜⎜⎜1000010000100001⎞⎠⎟⎟⎟⎟(1000010000100001)
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