log3x + logx3 =17/4. Find X?A. 3^4B. 3^(⅛)C. 3^(1/4)D. 3^(⅓)

To solve the equation, we first use the property of logarithms that states that the sum of the logarithms of two numbers is equal to the logarithm of the product of those numbers.

So, we can rewrite the equation as:

log3(x * x^3) = 17/4

This simplifies to:

log3(x^4) = 17/4

Next, we use the definition of a logarithm. If logb(a) = c, then b^c = a.

So, we can rewrite the equation as:

3^(17/4) = x^4

To solve for x, we take the fourth root of both sides:

x = (3^(17/4))^(1/4)

This simplifies to:

x = 3^(17/16)

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