To solve the inequality |2x + 3| 5, we need to consider two cases because of the absolute value. Case 1: 2x + 3 5 Subtract 3 from both sides: 2x 2 Divide both sides by 2: x 1 Case 2: -(2x + 3) 5 Distribute the negative sign: -2x - 3 5 Add 3 to both sides: -2x 8 Divide both sides by -2 (remember to flip the inequality sign because we're dividing by a negative number): x 5 is x 1.

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To solve the inequality |2x + 3| > 5, we need to consider two cases because of the absolute value.

Case 1: 2x + 3 > 5 Subtract 3 from both sides: 2x > 2 Divide both sides by 2: x > 1

Case 2: -(2x + 3) > 5 Distribute the negative sign: -2x - 3 > 5 Add 3 to both sides: -2x > 8 Divide both sides by -2 (remember to flip the inequality sign because we're dividing by a negative number): x < -4

So the solution set for the inequality |2x + 3| > 5 is x < -4 and x > 1.

Knowee AI · Accepted Answer

To solve the inequality |2x + 3| > 5, we need to consider two cases because of the absolute value.

Case 1: 2x + 3 > 5 Subtract 3 from both sides: 2x > 2 Divide both sides by 2: x > 1

Case 2: -(2x + 3) > 5 Distribute the negative sign: -2x - 3 > 5 Add 3 to both sides: -2x > 8 Divide both sides by -2 (remember to flip the inequality sign because we're dividing by a negative number): x < -4

So the solution set for the inequality |2x + 3| > 5 is x < -4 and x > 1.

The solution set of |2x + 3| > 5 is

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