Optical activity is a form of isomerism that arises from the asymmetry of a molecule, which allows it to rotate plane-polarized light. This property is observed in molecules that lack an internal plane of symmetry, making them chiral.

In the case of ethane-1,2-diamine, the molecule is symmetrical and does not have a chiral center, meaning it cannot exhibit optical activity.

However, if we consider a complex where ethane-1,2-diamine (en) acts as a ligand, such as [Co(en)3]3+, the situation changes. This complex is chiral (it has no plane of symmetry) and will show optical activity.

So, the answer to your question depends on the context. If you're asking about ethane-1,2-diamine itself, it won't show optical activity. But if you're asking about a complex where it acts as a ligand, it could potentially show optical activity.

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Optical activity is a form of isomerism that arises from the asymmetry of a molecule, which allows it to rotate plane-polarized light. This property is observed in molecules that lack an internal plane of symmetry, making them chiral.

In the case of ethane-1,2-diamine, the molecule is symmetrical and does not have a chiral center, meaning it cannot exhibit optical activity.

However, if we consider a complex where ethane-1,2-diamine (en) acts as a ligand, such as [Co(en)3]3+, the situation changes. This complex is chiral (it has no plane of symmetry) and will show optical activity.

So, the answer to your question depends on the context. If you're asking about ethane-1,2-diamine itself, it won't show optical activity. But if you're asking about a complex where it acts as a ligand, it could potentially show optical activity.

Knowee AI · Accepted Answer

Optical activity is a form of isomerism that arises from the asymmetry of a molecule, which allows it to rotate plane-polarized light. This property is observed in molecules that lack an internal plane of symmetry, making them chiral.

In the case of ethane-1,2-diamine, the molecule is symmetrical and does not have a chiral center, meaning it cannot exhibit optical activity.

However, if we consider a complex where ethane-1,2-diamine (en) acts as a ligand, such as [Co(en)3]3+, the situation changes. This complex is chiral (it has no plane of symmetry) and will show optical activity.

So, the answer to your question depends on the context. If you're asking about ethane-1,2-diamine itself, it won't show optical activity. But if you're asking about a complex where it acts as a ligand, it could potentially show optical activity.

The one that will show optical activity is:( en = ethane - 1,2 - diamine)

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