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Suppose you are to compare the average real estate value of houses in 2 cities. You collected samples from each city and compare their mean and variance. The data are given below.                         Group Sample size Sample mean ($000)Sample std. devCity A 37 230 17City B            40 200 15 Assuming unequal population variances and using the degrees of freedom of min(n1-1,n2-1), where n1 is the sample size of group 1 and n2 of group 2, calculate the 90% confidence interval of the difference between the means.

Question

Suppose you are to compare the average real estate value of houses in 2 cities. You collected samples from each city and compare their mean and variance. The data are given below.                         Group Sample size Sample mean ($000)Sample std. devCity A 37 230 17City B            40 200 15 Assuming unequal population variances and using the degrees of freedom of min(n1-1,n2-1), where n1 is the sample size of group 1 and n2 of group 2, calculate the 90% confidence interval of the difference between the means.

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Solution

To calculate the 90% confidence interval of the difference between the means, we will use the formula for the confidence interval for the difference between two means with unequal variances:

CI = (M1 - M2) ± t*√((s1^2/n1) + (s2^2/n2))

where:

  • M1 and M2 are the sample means,
  • s1 and s2 are the sample standard deviations,
  • n1 and n2 are the sample sizes,
  • t is the t-value from the t-distribution table corresponding to the desired level of confidence and degrees of freedom.

Given data:

  • For City A: n1 = 37, M1 = 230, s1 = 17
  • For City B: n2 = 40, M2 = 200, s2 = 15

The degrees of freedom (df) is the minimum of (n1-1) and (n2-1), so df = min(37-1, 40-1) = 36.

For a 90% confidence level and 36 degrees of freedom, the t-value (from the t-distribution table) is approximately 1.69.

Substituting these values into the formula, we get:

CI = (230 - 200) ± 1.69*√((17^2/37) + (15^2/40)) = 30 ± 1.69*√((289/37) + (225/40)) = 30 ± 1.69*√(7.81 + 5.63) = 30 ± 1.69*√13.44 = 30 ± 1.69*3.66 = 30 ± 6.18

So, the 90% confidence interval for the difference between the means is (23.82, 36.18).

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