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Find the coordinates of the turning point on the graph of y=−3(x−3)(x−8

Question

Find the coordinates of the turning point on the graph of y=−3(x−3)(x−8

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Solution

The turning point of a quadratic function is also known as the vertex. The vertex form of a quadratic function is y=a(x-h)^2+k, where (h,k) are the coordinates of the vertex.

In the given function y=-3(x-3)(x-8), we can find the x-coordinate of the vertex by finding the average of the roots of the equation. The roots are the values of x for which y=0, which are 3 and 8 in this case.

So, the x-coordinate of the vertex is (3+8)/2 = 5.5.

To find the y-coordinate of the vertex, we substitute x=5.5 into the equation:

y = -3(5.5-3)(5.5-8) = -3(2.5)(-2.5) = 18.75.

So, the coordinates of the turning point (vertex) are (5.5, 18.75).

This problem has been solved

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