If you begin the secant’s method near x = 2, which root is reached? How many iterations to achieve an error less than 10-5? solve

Compute two iterations for the function f(x) = x3 – 5x + 1 = 0 using the secant method, in which the real roots of the equation f(x) lies in the interval (0, 1).

Question 2 5 MarksFind a root of the following equation in the interval (0,1) using Newton-Raphson Method after threeiterations𝑥𝑒𝑥 − cos 𝑥 = 0Take Initial value 0.5.Note: Accuracy up to four decimal places is required. Here is a transcendental equation all thecalculation should be done in the radians mode.

Calculate the first five non-negative roots of the functionf(x) = x/a - tan(ax) ,consider a = 2, and a = 1. For each of the alternatives of the function f, and each of the roots, use the methods :. Bisection method,. False position method,. Fixed point method,. Newton-Raphson method,. Secant method.

Minimize f (x) = x4 − x + 1 using secant method with initial points x−1 = 3 and x0 = −3

Find a root of the equation 𝑥3 − 3𝑥 − 5 = 0, in the interval (2,3) using Bisection Method after threeIterations.Note: Accuracy up to four decimal places is required.