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he signs of ΔG, ΔH, and ΔS at 25°C are shown below for three reactions.reaction ΔG ΔH ΔSI. - + +II. - - +III. - - -Which reaction could go in the reverse direction at high temperature?Group of answer choicesIIIIIII and II

Question

he signs of ΔG, ΔH, and ΔS at 25°C are shown below for three reactions.reaction ΔG ΔH ΔSI. - + +II. - - +III. - - -Which reaction could go in the reverse direction at high temperature?Group of answer choicesIIIIIII and II

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Solution

The direction of a reaction can be predicted using the sign of the Gibbs free energy (ΔG). If ΔG is negative, the reaction will proceed in the forward direction. If ΔG is positive, the reaction will proceed in the reverse direction.

However, the question asks which reaction could go in the reverse direction at high temperatures. This is where the entropy change (ΔS) comes into play.

The relationship between ΔG, ΔH (enthalpy change), and ΔS is given by the equation ΔG = ΔH - TΔS, where T is the absolute temperature.

At high temperatures, the TΔS term becomes significant. If ΔS is positive, then TΔS is also positive and as T increases, TΔS increases. This means that ΔG could become positive at high temperatures, even if ΔH is negative, causing the reaction to proceed in the reverse direction.

So, looking at the reactions given:

I. ΔG is negative, ΔH is positive, and ΔS is positive. This reaction will proceed in the forward direction at all temperatures because ΔH - TΔS will always be negative (since both ΔH and TΔS are positive).

II. ΔG is negative, ΔH is negative, and ΔS is positive. This reaction will also proceed in the forward direction at all temperatures because ΔH - TΔS will always be negative (since ΔH is negative and TΔS is positive).

III. ΔG is negative, ΔH is negative, and ΔS is negative. This reaction could potentially go in the reverse direction at high temperatures. This is because although ΔH is negative, TΔS is also negative (since ΔS is negative). As T increases, TΔS becomes more negative, and it's possible that ΔH - TΔS could become positive, making ΔG positive and causing the reaction to proceed in the reverse direction.

So, the answer to the question is III.

This problem has been solved

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