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The first four terms of a sequence are given. Can these terms be the terms of an arithmetic sequence?ln(2), ln(4), ln(8), ln(16),    Yes, the sequence is arithmetic.No, the sequence is not arithmetic.    If the sequence is arithmetic, find the common difference d. (If the sequence is not arithmetic, enter DNE.)d =

Question

The first four terms of a sequence are given. Can these terms be the terms of an arithmetic sequence?ln(2), ln(4), ln(8), ln(16),    Yes, the sequence is arithmetic.No, the sequence is not arithmetic.    If the sequence is arithmetic, find the common difference d. (If the sequence is not arithmetic, enter DNE.)d =

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Solution

To determine if a sequence is arithmetic, we need to check if the difference between consecutive terms is constant.

The given sequence is ln(2), ln(4), ln(8), ln(16).

Let's find the difference between the consecutive terms:

ln(4) - ln(2) = ln(4/2) = ln(2) ln(8) - ln(4) = ln(8/4) = ln(2) ln(16) - ln(8) = ln(16/8) = ln(2)

As we can see, the difference between each pair of consecutive terms is constant and equal to ln(2). Therefore, the sequence is arithmetic.

The common difference d of an arithmetic sequence is the difference between any two successive members. In this case, d = ln(2).

This problem has been solved

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