A group of 460 college students was surveyed over several typical weekdays, and 253 of them reported that they had eaten breakfast that day. Let B be the event of interest—that a college student eats breakfast.Based on this information, what is the estimate of P(B), the probability that a randomly chosen college student eats breakfast?
Question
A group of 460 college students was surveyed over several typical weekdays, and 253 of them reported that they had eaten breakfast that day. Let B be the event of interest—that a college student eats breakfast.Based on this information, what is the estimate of P(B), the probability that a randomly chosen college student eats breakfast?
Solution 1
To estimate the probability P(B), we need to divide the number of students who reported eating breakfast by the total number of students surveyed.
Here's how you do it:
- Identify the total number of outcomes. In this
Solution 2
To estimate the probability P(B), we need to divide the number of students who reported eating breakfast by the total number of students surveyed.
So, P(B) = Number of students who ate breakfast / Total number of students surveyed
From the problem, we know that the number of students who ate breakfast is 253 and the total number of students surveyed is 460.
Therefore, P(B) = 253 / 460 = 0.55 (rounded to two decimal places)
So, the estimated probability that a randomly chosen college student eats breakfast is 0.55 or 55%.
Similar Questions
A survey of 36 students at the Wall College of Business showed the following majors: Accounting 10 Finance 6 Economics 4 Management 6 Marketing 10 Click here for the Excel Data FileFrom the 36 students, suppose you randomly select a student.a. What is the probability he or she is a management major? (Round your answer to 3 decimal places.)b. Which concept of probability did you use to make this estimate?
Students in a school were surveyed about their study habits. Forty-two percent of students said they study on weeknights and weekends, 47% said they studied on weekends, and 65% said they study either on weeknights or weekends. If you were to pick one student at random, what is the probability that he or she studies on a weeknight?40%60%45%50%
Pick a student at random. Let B denote the event that the student ate breakfast this morning; let M denote the event that the student is male.One of the following choices is larger than the other two. Which is it?P(B)P(B or M)P(B and M)One of the following choices is smaller than the other two. Which is it?P(B)P(B or M)P(B and M)
A survey showed that 25% of college students read newspapers on a regular basis and that 81% of college students regularly watch the news on TV. The survey also showed that 21% of college students both follow TV news regularly and read newspapers regularly.Answer the questions below. (If necessary, consult a list of formulas.)(a) What is the probability that a student watches TV news regularly, given that he or she regularly reads newspapers? Round your answer to 2 decimal places.(b) What is the probability that a randomly selected college student reads newspapers regularly, given that he or she watches TV news regularly? Round your answer to 2 decimal places.
On a particular day, a restaurant that is open for lunch and dinner had 186 customers. Each customer came in for one meal. An employee recorded at which meal each customer came in and whether the customer ordered dessert. The data are summarized in the table below.DessertNo dessertLunch15 69Dinner39 63Suppose a customer from that day is chosen at random.Answer each part. Do not round intermediate computations, and round your answers to the nearest hundredth.(If necessary, consult a list of formulas.)(a)What is the probability that the customer did not order dessert?(b)What is the probability that the customer came for dinner or did not order dessert?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.