A man standing on a bridge throws a stone horizontally with a horizontal velocity of 20 m/s. The stone hits the water below 3 s later. The height of the bridge is closest to?Question 9Answera. 20 m highb.45 m highc.50 m highd.60 m highe.20 m high
Question
A man standing on a bridge throws a stone horizontally with a horizontal velocity of 20 m/s. The stone hits the water below 3 s later. The height of the bridge is closest to?Question 9Answera. 20 m highb.45 m highc.50 m highd.60 m highe.20 m high
Solution
To solve this problem, we need to use the equation of motion that describes the vertical displacement of an object under the influence of gravity. This equation is:
h = 0.5 * g * t^2
where:
- h is the height of the bridge,
- g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth), and
- t is the time it takes for the stone to hit the water.
Substituting the given values into the equation, we get:
h = 0.5 * 9.8 m/s^2 * (3 s)^2 h = 0.5 * 9.8 m/s^2 * 9 s^2 h = 44.1 m
So, the height of the bridge is closest to 45 m. Therefore, the correct answer is (b) 45 m high.
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