The atomic radius of BCC structure is……………a.a√/4b.None of thesec.a/2d.a√3/4

The atomic radius (r) of a Body-Centered Cubic (BCC) structure can be found using the formula for the diagonal of the cube, which is √3a, where a is the edge length of the cube.

In a BCC structure, the diagonal of the cube is made up of 4 radii (2 atomic radii from the center atom and 1 atomic radius from each of the corner atoms).

So, we have:

√3a = 4r

Solving for r (the atomic radius), we get:

r = √3a / 4

So, the atomic radius of a BCC structure is a√3/4. Therefore, the answer is d. a√3/4.