Complete below code of Preorder traversalPreorder(node* root){If(a-----------------){cout<<root->data;b--------------------------;preorder(root->right);}} a.NULL b.root->lefta.root==NULL b.Preorder(root->left);a.root!=NULL b.Preorder(root->left);a.root!=NULL b.root->left
Question
Complete below code of Preorder traversalPreorder(node* root){If(a-----------------){cout<<root->data;b--------------------------;preorder(root->right);}} a.NULL b.root->lefta.root==NULL b.Preorder(root->left);a.root!=NULL b.Preorder(root->left);a.root!=NULL b.root->left
Solution
The correct completion of the code for Preorder traversal would be:
Preorder(node* root){
If(root != NULL){
cout<<root->data;
Preorder(root->left);
preorder(root->right);
}
}
Here, the correct options for a and b are:
a. root != NULL b. Preorder(root->left)
This code first checks if the root is not NULL, then it prints the root data. After that, it recursively calls the Preorder function for the left subtree and then for the right subtree. This is the standard procedure for a Preorder traversal in a binary tree (root, left, right).
Similar Questions
In preorder traversal of a binary tree the second step is ____________Select one:a. traverse the right subtreeb. traverse the left subtreec. traverse right subtree and visit the rootd. visit the root
The inorder and preorder traversal of a binary tree are Inorder: d b e a p q r PreOrder: a b d e q p r The postorder traversal of the binary tree is: (A) d e b p r q a (B) e d b r p q a (C) e d b p r q a (D) d e p r b q a
Given the root of a binary tree, return the preorder traversal of its nodes' values. Example 1:Input: root = [1,null,2,3]Output: [1,2,3]Example 2:Input: root = []Output: []Example 3:Input: root = [1]Output: [1] Constraints:The number of nodes in the tree is in the range [0, 100].-100 <= Node.val <= 100 Follow up: Recursive solution is trivial, could you do it iteratively?
Implement Inorder, preorder and postorder tree traversal techniques.Unlike linear data structures (Array, Linked List, Queues, Stacks, etc) which have only one logical way to traverse them, trees can be traversed in different ways. The following are the generally used methods for traversing trees:INORDER TRAVERSAL:Traverse the left subtree, i.e., call Inorder(left->subtree)Visit the root.Traverse the right subtree, i.e., call Inorder(right->subtree)PREORDER TRAVERSAL:Visit the root.Traverse the left subtree, i.e., call Preorder(left->subtree)Traverse the right subtree, i.e., call Preorder(right->subtree)Postorder Traversal:Traverse the left subtree, i.e., call Postorder(left->subtree)Traverse the right subtree, i.e., call Postorder(right->subtree)Visit the rootInput Format:The input consists of two lines:The first line contains the number of nodes in the binary tree.The second line contains the values of the nodes, separated by spaces, representing the binary tree.Output Format:First Line contains the Inorder TraversalSecod Line contains the Preorder TravesalThird Line contains th Postorder Traversal Sample input6 5 3 8 1 4 10Sample output1 3 4 5 8 10 5 3 1 4 8 10 1 4 3 10 8 5
ind a binary tree whose preorder and inorder traversals create thesame result
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.