ABCD is a cyclic quadrilateral, ABX is a straight line and PQ is a tangent to the circle at A�Angle °CBX 85= , angle °BAQ 55= and angle °CAD 42=

ABCD is cyclic quadrilateral Sides AB and DC, when produced, meet at E, and sides BC and AD, When produced, meet at F. If ∠BFA=60° and ∠AED=30°, then the measure of ∠ABC is:Choices:- 85° 65° 75° 90°

2. ABCD  is a cyclic quadrilateral such that  AB  is a diameter of the circle circumscribing it and  ∠ADC  =  150∘ . Then  ∠BAC  is equal to

ABCD is a trapezium and P, Q are the mid points of the diagonals AC and BD respectively. Then PQ is equal to

A quadrilateral ABCD is inscribed in a circle. Suppose that DA =BC= 2 and AB = 4. Let E be the intersection point of lines BC and DA. Suppose that angle <AEB = 60 and that CD <AB. Calculate the radius of the circle.

If tangents PA & PB from a point P to a circle with centre O are inclined to each other at an angle of 110º, then the   equal to :A 65º B 55º C 45º D  35º