A uniform rod of mass  M and length  ℓ is moving on a smooth horizontal plane, such that its one end is moving with a velocity  v0 and other end is moving with a velocity  2v0 in the same direction as shown. Then, the kinetic energy of the rod is

A uniform rod of mass m, length l is placed on smooth horizontal surface. An impulse J is given horizontally at one end perpendicular to the length of rod. Kinetic energy of the rod after impulse is given, is

1. The bent rod has a mass p per unit length and rotates about the z-axis with an angularvelocity ur. Determine the angular momentum L of the rod about the fixed origin of theaxes, which are attached to the rod. Also find the kinetic energy T of the rod I KineticEnergy is given by: I=ll2 a. L I (the dot product of o and L)

Uniform rod of mass m and length a,P point is at distance a from near end,and at extension of the rod.

The diagram shows a thin rod of uniform mass distribution pivoted about one end by a pin passing through that point. The mass of the rod is 0.600 kg and its length is 2.00 m. When the rod is released from its horizontal position, it swings down to the vertical position as shown.(a) Determine the speed of its center of gravity at its lowest position. Consider the conservation of energy of the center of mass of the rod. What is the relationship between angular and tangential velocities? m/s

A body of mass  kg is moving with a velocity of  m/s. Its kinetic energy will b