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In a linear programming problem, the constraints are:constraint 1: 9x1 + 28x2 ≤ 63constraint 2: 16x1 + 52x2 ≤ 211What value from constraint 2 can the slope of the objective function not exceed in order for the optimal solution point to remain optimal?Another way to ask this is, what's the slope of constraint 2?Round your solution to 2 decimal places.

Question

In a linear programming problem, the constraints are:constraint 1: 9x1 + 28x2 ≤ 63constraint 2: 16x1 + 52x2 ≤ 211What value from constraint 2 can the slope of the objective function not exceed in order for the optimal solution point to remain optimal?Another way to ask this is, what's the slope of constraint 2?Round your solution to 2 decimal places.

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Solution

The slope of a linear equation is calculated by dividing the coefficient of x1 by the coefficient of x2. In constraint 2, the coefficients are 16 and 52 respectively.

So, the slope of constraint 2 is 16/52 = 0.3076923076923077

Rounding this to two decimal places, the slope is 0.31.

Therefore, the slope of the objective function cannot exceed 0.31 for the optimal solution point to remain optimal.

This problem has been solved

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