What is the output when following code is executed ?>>> str1 = 'hello'>>> str2 = ','>>> str3 = 'world'>>> str1[-1:]
Question
What is the output when following code is executed ?>>> str1 = 'hello'>>> str2 = ','>>> str3 = 'world'>>> str1[-1:]
Solution 1
The output will be 'o'.
Here's the step by step explanation:
- str1 = 'hello' assigns the string 'hello' to the variable str1.
- str2 = ',' assigns the string ',' to the variable str2.
- str3 = 'world' assigns the string 'world' to the variable str3.
- str1[-1:] is a slice operation that gets the last character of the string str1. In Python, negative indexing starts from the end of the string. So, str1[-1] will be the last character 'o'. The colon (:) in the slice operation means to get all characters from that position to the end of the string. Since there's only one character at the end, it returns 'o'.
Solution 2
The output of the code will be 'o'.
Here's the step by step explanation:
- str1 = 'hello' assigns the string 'hello' to the variable str1.
- str1[-1:] is a slice that gets the last character of the string str1. In Python, negative indexing starts from the end of the string. So, str1[-1] refers to the last character of str1, which is 'o'.
- The colon in str1[-1:] indicates slicing up to the end of the string. Since there's only one character from the last, it returns 'o'.
So, the output of the code str1[-1:] is 'o'.
Solution 3
The output will be 'o'.
Here's the step by step explanation:
In Python, you can use negative indexing to access elements from the end of a string or list. The index -1 refers to the last item, -2 refers to the second last item, and so on.
In the given code, str1[-1:] is used. This means we are accessing the string str1 from the last character to the end of the string. Since there is only one character at the end, it will return 'o', which is the last character of the string 'hello'.
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