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On a certain day, Rohit started with p newspapers. From morning to noon, he sold 40% of the papers, and between noon and evening he sold 60% of the remaining. Then he realised that had he sold double the number of newspapers than he sold in the afternoon, he would have had to borrow 12 papers from another vendor. Find p. radio_button_unchecked 108 radio_button_unchecked 100 radio_button_unchecked 96 radio_button_unchecked 72

Question

On a certain day, Rohit started with p newspapers. From morning to noon, he sold 40% of the papers, and between noon and evening he sold 60% of the remaining. Then he realised that had he sold double the number of newspapers than he sold in the afternoon, he would have had to borrow 12 papers from another vendor. Find p.

radio_button_unchecked 108

radio_button_unchecked 100

radio_button_unchecked 96

radio_button_unchecked 72

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Solution

Let's solve this step by step:

  1. Rohit started with p newspapers.

  2. From morning to noon, he sold 40% of the papers. So, he was left with 60% of p, which is 0.6p.

  3. Between noon and evening, he sold 60% of the remaining. So, he was left with 40% of 0.6p, which is 0.4*0.6p = 0.24p.

  4. Then he realised that had he sold double the number of newspapers than he sold in the afternoon, he would have had to borrow 12 papers from another vendor. This means that the number of papers he sold in the afternoon is equal to the number of papers he had left plus 12.

    Let's denote the number of papers he sold in the afternoon as x. According to the problem, x = 0.24p + 12.

    But we also know that he sold 60% of the papers he had at noon in the afternoon, which means x = 0.6*0.6p = 0.36p.

  5. Now we have two equations with two variables, which we can solve to find the value of p:

    0.24p + 12 = 0.36p 12 = 0.36p - 0.24p 12 = 0.12p p = 12 / 0.12 p = 100

So, Rohit started with 100 newspapers. The correct answer is:

radio_button_checked 100

This problem has been solved

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