What is the factorization of the trinomial below?12x2 - x - 35A.(6x - 7)(x + 5)B.(6x + 7)(x - 5)C.(4x - 7)(3x + 5)D.(4x + 7)(3x - 5)SUBMITarrow_backPREVIOUS
Question
What is the factorization of the trinomial below?12x2 - x - 35A.(6x - 7)(x + 5)B.(6x + 7)(x - 5)C.(4x - 7)(3x + 5)D.(4x + 7)(3x - 5)SUBMITarrow_backPREVIOUS
Solution
The factorization of the trinomial 12x^2 - x - 35 can be found by looking for two numbers that multiply to (12*-35) = -420 and add to -1 (the coefficient of x).
Those two numbers are -20 and 21, because -20*21 = -420 and -20 + 21 = 1.
We can then rewrite the middle term of the trinomial as -20x + 21x:
12x^2 - 20x + 21x - 35
Next, we can factor by grouping:
4x(3x - 5) + 7(3x - 5)
Finally, we can factor out the common binomial term to get the final factorization:
(4x + 7)(3x - 5)
So, the correct answer is D. (4x + 7)(3x - 5)
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