Determine the area of the parallelogram with vertices ( -5,6), ( -1,6), (-3, 3), and (-7, 3).Question 1Select one:A.12 sq. unitB.10 sq. unitC.15 sq. unitD.14 sq. unitClear my choice

To determine the area of the parallelogram with vertices (-5,6), (-1,6), (-3,3), and (-7,3), we can use the formula for the area of a parallelogram.

Step 1: Find the length of one of the sides of the parallelogram. We can use the distance formula to find the distance between two points. Let's find the distance between (-5,6) and (-1,6):

d = √((x2 - x1)^2 + (y2 - y1)^2) = √((-1 - (-5))^2 + (6 - 6)^2) = √(4^2 + 0^2) = √16 = 4

So, the length of one side of the parallelogram is 4 units.

Step 2: Find the height of the parallelogram. We can use the distance formula again to find the distance between two points. Let's find the distance between (-3,3) and (-7,3):

d = √((x2 - x1)^2 + (y2 - y1)^2) = √((-7 - (-3))^2 + (3 - 3)^2) = √((-4)^2 + 0^2) = √16 = 4

So, the height of the parallelogram is 4 units.

Step 3: Calculate the area of the parallelogram using the formula: Area = base x height. In this case, the base is the length of one side (4 units) and the height is the height we found (4 units).

Area = 4 x 4 = 16 square units

Therefore, the area of the parallelogram is 16 square units.