The metastable state of a laser active medium with 3 energy levels is 1.4 eVabove the non-excited level at 0eV. If the non-radiative transition from the excitedstate to metastable state is 1.15μm, find out(a) Position of excited state in eV.(b) Laser photon wavelength(c) Wavelength of the pumping source
Question
The metastable state of a laser active medium with 3 energy levels is 1.4 eVabove the non-excited level at 0eV. If the non-radiative transition from the excitedstate to metastable state is 1.15μm, find out(a) Position of excited state in eV.(b) Laser photon wavelength(c) Wavelength of the pumping source
Solution
(a) Position of excited state in eV
The energy of the non-radiative transition from the excited state to the metastable state can be calculated using the formula:
E = hc/λ
where: E is the energy, h is Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength (1.15 x 10^-6 m).
Substituting the values into the formula, we get:
E = (6.626 x 10^-34 J.s)(3 x 10^8 m/s) / (1.15 x 10^-6 m)
E = 1.73 x 10^-19 J
To convert this energy to electron volts (eV), we use the conversion factor 1 eV = 1.6 x 10^-19 J. Therefore,
E = 1.73 x 10^-19 J / 1.6 x 10^-19 J/eV
E = 1.08 eV
The position of the excited state is the sum of the energy of the metastable state and the energy of the non-radiative transition. Therefore,
Position of excited state = 1.4 eV + 1.08 eV = 2.48 eV
(b) Laser photon wavelength
The energy of the laser photon is the difference between the energy of the metastable state and the non-excited state, which is 1.4 eV. To find the wavelength of the laser photon, we can use the formula:
λ = hc/E
Substituting the values into the formula, we get:
λ = (6.626 x 10^-34 J.s)(3 x 10^8 m/s) / (1.4 eV)(1.6 x 10^-19 J/eV)
λ = 8.85 x 10^-7 m = 885 nm
(c) Wavelength of the pumping source
The energy of the pumping source is the same as the energy of the excited state, which is 2.48 eV. To find the wavelength of the pumping source, we can use the formula:
λ = hc/E
Substituting the values into the formula, we get:
λ = (6.626 x 10^-34 J.s)(3 x 10^8 m/s) / (2.48 eV)(1.6 x 10^-19 J/eV)
λ = 5.01 x 10^-7 m = 501 nm
Similar Questions
Stimulated absorption rate depends ona.Number of atoms in lower stateb.Energy of input photonsc.Both of them
For Laser action to occur, the medium used must have at least three energy level. Why is three the minimum number?A. Medium is not stableB. Excitation (pumping) is not possible in two energy levelsC. Population inversion is possible only in three energy levelsD. Population inversion is not possible in less than three energy levels
What would be the photon energy of light emitted from a transition between the = 5 state and the ground state? Show all your working and give your final answer in eV.
28. Which transition in an excited hydrogen atom will emit the longest wavelength of light?1 pointE5 to E1E4 to E1E3 to E1E2 to E1
A hydrogen atom initially in the ground level absorbs a photon,which excites it to the n = 4 level. Determine the wavelength andfrequency of photon.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.