Factorise 6a2−a−176 completely.
Question
Factorise 6a2−a−176 completely.
Solution
Sure, here is the step-by-step solution to factorize the given expression:
-
The given expression is 6a^2 - a - 176.
-
We need to factorize this quadratic equation in the form of (px + q)(rx + s).
-
For this, we need to find two numbers such that their product is equal to the product of the coefficient of a^2 (which is 6) and the constant term (which is -176), and their sum is equal to the coefficient of a (which is -1).
-
The two numbers that satisfy these conditions are -8 and 22, because -822 = -1766 and -8 + 22 = -1.
-
So, we can write the middle term (-a) as -8a + 22a.
-
The expression becomes 6a^2 - 8a + 22a - 176.
-
Now, we can factor by grouping. The first two terms can be grouped together, and the last two terms can be grouped together.
-
This gives us 2a(3a - 4) + 22(3a - 4).
-
Now, you can see that (3a - 4) is a common factor.
-
So, the factorized form of the given expression is (2a + 22)(3a - 4).
So, 6a^2 - a - 176 = (2a + 22)(3a - 4).
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.