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A computer with cache access time of 100 ns and hit ratio of 0·9 produces an average access time of

Question

A computer with cache access time of 100 ns and hit ratio of 0·9 produces an average access time of

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Solution

You haven't provided the memory access time, which is a crucial piece of information needed to calculate the average access time. However, I can provide you with the formula to calculate the average access time:

Average Access Time = Hit Time + Miss Rate * Miss Penalty

In this case, the hit time is the cache access time (100 ns), the hit ratio is 0.9 (so the miss rate is 1 - 0.9 = 0.1), but we don't have the miss penalty, which is the memory access time. If you provide that, we can calculate the average access time.

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Similar Questions

A computer with cache access time of 100 ns and hit ratio of 0·9 produces an average access time of ans. b)200ns d)none of these. c)190ns a)250ns one line answer

A small computer has a direct-mapped data cache of size 1 kilo Bytes. lts block size is 32 bytes, hit time is 2 processor clock cycles, and, the miss penalty is 20 processor clock cyclesWhile running a loop, in each iteration data (of size 1 byte) is accessed from memory addresses 6, 522, 768, 1028. If the loop iterates 10 times, compute the average data access time for the loop.

What is the cache hit ratio. if memory access takes 20 ns with cache and 110 ns without it (cache uses a 10 ns memory)?

If the same 1 kilo Byte cache had been organized as a two-way set associative cache (other specifications remaining the same), then what would have been the average data access time for the loop?

If the average time to handle a page fault is 10 milliseconds, and a memory access requires 1 microsecond, then achieving a 99.99% hit ratio would lead to an average memory access time ofa.1 millisecondb.1.9999 millisecondsc.1.9999 microsecondsd.9.999 microseconds

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