Find the solution of the system of equations.2, x, minus, 10, y, equals, minus, 282x−10y=−28minus, 10, x, plus, 10, y, equals, minus, 20−10x+10y=−20
Question
Find the solution of the system of equations.2, x, minus, 10, y, equals, minus, 282x−10y=−28minus, 10, x, plus, 10, y, equals, minus, 20−10x+10y=−20
Solution
Sure, let's solve the system of equations step by step.
The system of equations is:
- 2x - 10y = -28
- -10x + 10y = -20
Step 1: Simplify the equations if possible. The first equation can be simplified by dividing all terms by 2, and the second equation can be simplified by dividing all terms by 10:
- x - 5y = -14
- -x + y = -2
Step 2: Add the two equations together. The y terms will cancel out:
0 = -16
This is a contradiction, because 0 is not equal to -16. Therefore, the system of equations has no solution.
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