On a street, there are N individuals (numbered from 1 to N) positioned along the line. Each person's position is denoted by Xi.Here's the situation: among these people, one person is unknowingly carrying the COVID-19 virus. The virus spreads if the distance between an infected person and a healthy person is no more than 2 units. As time goes on, a certain group of individuals (depending on who the initial infected person is) will become infected. Let's refer to the size of this group as the final count of infected people.Your goal is to print the smallest and largest possible number of people who could end up infected. This means finding the minimum and maximum counts of infected individuals, considering both the most favorable and the least favorable scenarios for how the virus spreads among the people on the street.Input FormatThe first line of each test case contains a single integer N.The second line contains N space-separated integers X1, X2, ..., XN.Constraints2 ≤ N ≤ 80 ≤ Xi ≤ 10 for each valid i0 ≤ X1 < X2 < ... < XNOutput FormatPrint a single line containing two space-separated integers ― the minimum and maximum possible final number of infected people.Sample Input 021 2Sample Output 02 2Sample Input 123 6Sample Output 11 1Contest ends in 5 hoursSubmissions: 375Max Score: 10Rate This Challenge: More C1#include <stdio.h>2#include <string.h>3#include <math.h>4#include <stdlib.h>56int main() {78 /* Enter your code here. Read input from STDIN. Print output to STDOUT */ 9 return 0;10}11
Question
On a street, there are N individuals (numbered from 1 to N) positioned along the line. Each person's position is denoted by Xi.Here's the situation: among these people, one person is unknowingly carrying the COVID-19 virus. The virus spreads if the distance between an infected person and a healthy person is no more than 2 units. As time goes on, a certain group of individuals (depending on who the initial infected person is) will become infected. Let's refer to the size of this group as the final count of infected people.Your goal is to print the smallest and largest possible number of people who could end up infected. This means finding the minimum and maximum counts of infected individuals, considering both the most favorable and the least favorable scenarios for how the virus spreads among the people on the street.Input FormatThe first line of each test case contains a single integer N.The second line contains N space-separated integers X1, X2, ..., XN.Constraints2 ≤ N ≤ 80 ≤ Xi ≤ 10 for each valid i0 ≤ X1 < X2 < ... < XNOutput FormatPrint a single line containing two space-separated integers ― the minimum and maximum possible final number of infected people.Sample Input 021 2Sample Output 02 2Sample Input 123 6Sample Output 11 1Contest ends in 5 hoursSubmissions: 375Max Score: 10Rate This Challenge: More C1#include <stdio.h>2#include <string.h>3#include <math.h>4#include <stdlib.h>56int main() {78 /* Enter your code here. Read input from STDIN. Print output to STDOUT */ 9 return 0;10}11
Solution
This problem can be solved using a simple approach. Here is a step-by-step guide on how to solve it:
- Read the number of individuals (N) from the input.
- Read the positions of the individuals (X1, X2, ..., XN) from the input.
- Initialize two variables, min and max, to 1. These variables will hold the minimum and maximum possible number of infected people.
- Iterate over the positions of the individuals. For each position, calculate the number of individuals within a distance of 2 units. If this number is greater than max, update max. If this number is less than min, update min.
- After iterating over all positions, print the values of min and max.
Here is a Python code snippet that implements this approach:
N = int(input())
positions = list(map(int, input().split()))
min_infected = max_infected = 1
for i in range(N):
left = i - 1
right = i + 1
count = 1
while left >= 0 and positions[i] - positions[left] <= 2:
count += 1
left -= 1
while right < N and positions[right] - positions[i] <= 2:
count += 1
right += 1
min_infected = min(min_infected, count)
max_infected = max(max_infected, count)
print(min_infected, max_infected)
This code first reads the number of individuals and their positions. It then iterates over the positions and for each position, it counts the number of individuals within a distance of 2 units. It updates the minimum and maximum number of infected individuals accordingly. Finally, it prints the minimum and maximum number of infected individuals.
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