Fabry disease in humans is a X-linked disease. The probability (in percentage) fora phenotypically normal father and a carrier mother to have a son with Fabrydisease is ____________.
Question
Fabry disease in humans is a X-linked disease. The probability (in percentage) fora phenotypically normal father and a carrier mother to have a son with Fabrydisease is ____________.
Solution
Fabry disease is an X-linked genetic disorder. This means that the gene causing the disease is located on the X chromosome.
In humans, females have two X chromosomes (XX) and males have one X and one Y chromosome (XY).
A carrier mother for Fabry disease has one normal X chromosome and one X chromosome with the Fabry disease gene. A phenotypically normal father has a normal X and Y chromosome.
When they have a child, the mother can pass on either her normal X chromosome or her X chromosome with the Fabry disease gene. The father will pass on either his X or Y chromosome.
For a son to be born, the father must pass on his Y chromosome (as the Y chromosome determines male sex). The son's X chromosome can come from either the mother's normal X chromosome or her X chromosome with the Fabry disease gene.
Therefore, the probability of them having a son with Fabry disease is 50%. This is because there is a 50% chance the mother will pass on her X chromosome with the Fabry disease gene.
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