Number_Of_ComparisonsWrite a C program that creates an array based on user input and determines the number of comparisons made while searching for a target element, also provided by the user.
Question
Number_Of_ComparisonsWrite a C program that creates an array based on user input and determines the number of comparisons made while searching for a target element, also provided by the user.
Solution
Sure, here is a simple C program that does what you asked for:
#include <stdio.h>
int main() {
int n, i, target, count = 0;
printf("Enter the size of the array: ");
scanf("%d", &n);
int arr[n];
printf("Enter the elements of the array: ");
for(i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
printf("Enter the target element: ");
scanf("%d", &target);
for(i = 0; i < n; i++) {
count++;
if(arr[i] == target) {
printf("Target element found after %d comparisons\n", count);
return 0;
}
}
printf("Target element not found after %d comparisons\n", count);
return 0;
}
This program first asks the user for the size of the array, then it asks for each element of the array. After that, it asks for the target element. It then goes through each element of the array, comparing it with the target. If it finds the target, it prints the number of comparisons made and ends. If it doesn't find the target after going through the whole array, it prints the number of comparisons made.
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