Given two integers a and b, write a function lcmAndGcd() to compute their LCM and GCD. The function takes two integers a and b as input and returns a list containing their LCM and GCD.Example 1:Input: a = 5 , b = 10Output: 10 5Explanation: LCM of 5 and 10 is 10, while thier GCD is 5.Input: a = 14 , b = 8Output: 56 2Explanation: LCM of 14 and 8 is 56, while thier GCD is 2.Expected Time Complexity: O(log(min(a, b))Expected Auxiliary Space: O(1)Constraints:
Question
Given two integers a and b, write a function lcmAndGcd() to compute their LCM and GCD. The function takes two integers a and b as input and returns a list containing their LCM and GCD.Example 1:Input: a = 5 , b = 10Output: 10 5Explanation: LCM of 5 and 10 is 10, while thier GCD is 5.Input: a = 14 , b = 8Output: 56 2Explanation: LCM of 14 and 8 is 56, while thier GCD is 2.Expected Time Complexity: O(log(min(a, b))Expected Auxiliary Space: O(1)Constraints:
Solution
Sure, here is a Python function that calculates the LCM and GCD of two numbers:
def gcd(a, b):
if a == 0:
return b
return gcd(b % a, a)
def lcm(a, b):
return (a / gcd(a, b)) * b
def lcmAndGcd(a, b):
return [lcm(a, b), gcd(a, b)]
Here's how it works:
-
The
gcdfunction uses the Euclidean algorithm to find the greatest common divisor ofaandb. Ifais 0, it returnsb. Otherwise, it recursively calls itself withb % aanda. -
The
lcmfunction calculates the least common multiple ofaandbby dividingaby their GCD and then multiplying byb. This works becausea * b = lcm(a, b) * gcd(a, b). -
The
lcmAndGcdfunction returns a list containing the LCM and GCD ofaandb.
The time complexity of this function is O(log(min(a, b))) because the Euclidean algorithm runs in logarithmic time. The auxiliary space complexity is O(1) because it uses a constant amount of space.
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Single File Programming QuestionProblem StatementSam is on a quest to decipher enchanted scrolls in an ancient temple that requires unveiling the HCF (Greatest Common Divisor) and LCM (Least Common Multiple) of two numbers. Write a program where Sam enters two positive integers, calculates the HCF and LCM using a for loop, and displays them.ExampleInput:6 3Output:HCF = 3LCM = 6Explanation:HCF (Greatest Common Divisor) of two numbers is the largest number that divides both of them without leaving a remainder.For 6 and 3, the common divisors are 1 and 3. The largest of these is 3, so the HCF is 3.LCM (Least Common Multiple) of two numbers is the smallest number that is a multiple of both.To find the LCM, we typically use the formula: LCM(a, b) = (a * b) / HCF(a, b).For 6 and 3, (6 * 3) / 3 = 18 / 3 = 6. So, the LCM is 6.Note: This question helps in clearing AMCAT exam.Input format :The input consists of two space-separated integers: n1 and n2.Output format :The first line prints "HCF = " followed by an integer which is the HCF of n1 and n2.The second line prints "LCM = " followed by an integer which is the LCM of n1 and n2.Refer to the sample outputs for the formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:1 ≤ n1, n2 ≤ 1000Sample test cases :Input 1 :6 3Output 1 :HCF = 3LCM = 6Input 2 :1000 1Output 2 :HCF = 1LCM = 1000
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