In a class of 50 students, each one plays either tennis or badminton orboth. 30 of the students play tennis and 32 play badminton.i. How many play both the game ?ii. How many play only tennis ?iii. How many play only badminton ?
Question
In a class of 50 students, each one plays either tennis or badminton orboth. 30 of the students play tennis and 32 play badminton.i. How many play both the game ?ii. How many play only tennis ?iii. How many play only badminton ?
Solution
i. To find out how many students play both games, we need to add the number of students who play tennis and the number of students who play badminton, then subtract the total number of students in the class. So, 30 (tennis players) + 32 (badminton players) - 50 (total students) = 12 students play both games.
ii. To find out how many students play only tennis, we subtract the number of students who play both games from the total number of tennis players. So, 30 (tennis players) - 12 (both games) = 18 students play only tennis.
iii. Similarly, to find out how many students play only badminton, we subtract the number of students who play both games from the total number of badminton players. So, 32 (badminton players) - 12 (both games) = 20 students play only badminton.
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