The basic Newton method is used for the solution of nonlinear problems
Question
The basic Newton method is used for the solution of nonlinear problems
Solution
The Newton method, also known as Newton-Raphson method, is a powerful technique used for finding approximately the roots of a real-valued function. It uses the idea that a continuous and differentiable function can be approximated by a straight line tangent to it. Here are the steps to implement the basic Newton method:
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Choose an initial guess x0 for the root of the function.
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Calculate the value of the function at x0 and the value of the derivative at x0.
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Use these values to calculate a better guess for the root using the formula: x1 = x0 - f(x0)/f'(x0).
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Repeat steps 2 and 3 using x1 instead of x0, and continue this process until the difference between two successive guesses is below a predetermined tolerance level, or until a maximum number of iterations has been reached.
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The last guess is then taken as the approximate root of the function.
This method is fast and effective, but it has some limitations. It requires the function to be differentiable, and the derivative to be non-zero at the root. Also, the initial guess needs to be reasonably close to the root for the method to converge.
Similar Questions
The Newton Raphson method is also called as ____________a)Chord methodb)Diameter methodc)Secant methodd)Tangent method
Consider the following nonlinear equation: 𝑓(𝑥)=𝑥^3−2𝑥^2−2𝑥+1=0 Solve for the root using interval halving with 𝑥=0 and 𝑥=1 Solve for the root using false position with 𝑥=0 and 𝑥=1 Solve for the root using fixed point with 𝑥_0=0 Solve for the root using Newton’s method with 𝑥_0=1
1. Numerical techniques mostly involveO Iterative method © Reduction method© Elimination method © None of the
The Iterative formula for Newton Raphson method is given by __________a)𝑥(1)=𝑥(0)+𝑓′(𝑥(0))𝑓(𝑥(0))x(1)=x(0)+ f(x(0))f ′ (x(0)) b)𝑥(1)=𝑥(0)−𝑓(𝑥(0))𝑓′(𝑥(0))x(1)=x(0)− f ′ (x(0))f(x(0)) c)𝑥(1)=𝑥(0)+𝑓(𝑥(0))𝑓′(𝑥(0))x(1)=x(0)+ f ′ (x(0))f(x(0)) d)𝑥(1)=𝑥(0)−𝑓′(𝑥(0))𝑓(𝑥(0))x(1)=x(0)− f(x(0))f ′ (x(0))
Minimize f (x) = x4 − x + 1 using Newton’s method with initial point x0 = 3.
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