A plane traveled from New York to San Diego at a speed of 215 km/ hr in 10.5 hours. The plane stopped for a 30 minute layover in St. Louis. How far did the plane travel?
Question
A plane traveled from New York to San Diego at a speed of 215 km/ hr in 10.5 hours. The plane stopped for a 30 minute layover in St. Louis. How far did the plane travel?
Solution
To find out how far the plane traveled, we need to multiply the speed of the plane by the time it was in the air.
Step 1: Convert the layover time to hours. 30 minutes is equal to 0.5 hours.
Step 2: Subtract the layover time from the total time. The total time was 10.5 hours, so after subtracting the 0.5 hour layover, the plane was in the air for 10 hours.
Step 3: Multiply the time the plane was in the air by the speed of the plane. The plane was traveling at a speed of 215 km/hr, so 215 km/hr * 10 hours = 2150 km.
So, the plane traveled 2150 km from New York to San Diego.
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