If 29.1 g of Co(NO3)2·6H2O present in 5 L of solution then molarity of solution will be (atomic weight of Co = 59 u)

To calculate the molarity of the solution, we need to follow these steps:

1. First, calculate the molar mass of Co(NO3)2·6H2O. The molar mass is calculated by adding the atomic masses of all the atoms in the compound.

   Molar mass of Co(NO3)2·6H2O = atomic mass of Co + 2*(atomic mass of N + 3atomic mass of O) + 6(2*atomic mass of H + atomic mass of O)

   Given atomic mass of Co = 59 u, atomic mass of N = 14 u, atomic mass of O = 16 u, and atomic mass of H = 1 u, we get:

   Molar mass of Co(NO3)2·6H2O = 59 u + 2*(14 u + 316 u) + 6(2*1 u + 16 u) = 291 g/mol

2. Next, convert the mass of Co(NO3)2·6H2O from grams to moles. This is done by dividing the given mass by the molar mass.

   Moles of Co(NO3)2·6H2O = 29.1 g / 291 g/mol = 0.1 mol

3. Finally, calculate the molarity of the solution. Molarity is defined as the number of moles of solute per liter of solution.

   Molarity = moles of solute / volume of solution in liters = 0.1 mol / 5 L = 0.02 M

So, the molarity of the solution is 0.02 M.