DC shunt generator has an induced voltage on open-circuit of 127 volts. When the machine is on load, the terminal voltage is 120 volts. i.       The load current equals to ……… if the field circuit resistance is 15 ohms

To answer this question, we first need to understand the basic principles of a DC shunt generator. In a DC shunt generator, the field windings are connected in parallel (shunt) with the armature windings. This means that the voltage across the field windings is the same as the terminal voltage of the generator.

The question states that the open-circuit voltage (the voltage when no load is connected) is 127 volts, and the terminal voltage (the voltage when the generator is on load) is 120 volts. The difference between these two voltages is the voltage drop across the field windings when the generator is on load.

Voltage drop = Open-circuit voltage - Terminal voltage Voltage drop = 127 volts - 120 volts = 7 volts

The question also states that the field circuit resistance is 15 ohms. We can use Ohm's law (Voltage = Current x Resistance) to find the current flowing through the field windings.

Field current = Voltage drop / Field resistance Field current = 7 volts / 15 ohms = 0.467 amps

Therefore, the load current equals to 0.467 amps.