mimimum number of carbons required to an alkene to form optical isomerism
Question
mimimum number of carbons required to an alkene to form optical isomerism
Solution
The minimum number of carbon atoms required for an alkene to show optical isomerism is four. Here's why:
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Optical isomerism occurs due to the presence of a chiral center in a molecule. A chiral center is a carbon atom that is attached to four different groups.
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In alkenes, optical isomerism can occur when there is a carbon-carbon double bond, with each carbon of the double bond attached to two different groups. This is known as geometric or cis-trans isomerism.
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However, for an alkene to show optical isomerism, it must have at least two chiral centers. This is because the presence of a plane of symmetry (which would be present in an alkene with only one chiral center) would make the molecule achiral, i.e., not optically active.
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Therefore, the minimum number of carbon atoms required for an alkene to show optical isomerism is four - two for the carbon-carbon double bond, and two more to allow each carbon of the double bond to be attached to two different groups.
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How to find optical isomerism also give example
The alkenes are unsaturated hydrocarbons. They form a homologous series, the members ofwhich have the same chemical properties.They undergo addition reactions and are easily oxidised.(a) The following hydrocarbons are isomers.CH 3 CH CH CH 2CH 3CH 3 CH 2 CH 2 CH CH 2(i) Explain why these two hydrocarbons are isomers................................................................................................................................................................................................................................................................... [2](ii) Give the structural formula of another hydrocarbon which is isomeric with the above.[1](b) Give the structural formula and name of each of the products of the following additionreactions.(i) ethene and brominestructural formula of productname of product ................................................................................................... [2](ii) propene and hydrogenstructural formula of productname of product ................................................................................................... [2](iii) but-1-ene and waterstructural formula of productname of product ................................................................................................... [2]PhysicsAndMathsTutor.com
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