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. The two-dimensional random variables ( ๐‘‹ , ๐‘Œ ) (X,Y) have the joint density function: ๐‘“ ( ๐‘ฅ , ๐‘ฆ ) = 2 ๐‘ฅ + ๐‘ฆ 20 , ๐‘ฅ = 0 , 1 , 2 , ย andย  ๐‘ฆ = 0 , 1 , 2 f(x,y)= 20 2x+y โ€‹ ,x=0,1,2,ย andย y=0,1,2 (a) Find the joint cumulative distribution function (CDF) of ๐‘‹ X and ๐‘Œ Y. (b) Determine if ๐‘‹ X and ๐‘Œ Y are independent.

Question

. The two-dimensional random variables ( ๐‘‹ , ๐‘Œ ) (X,Y) have the joint density function:

๐‘“ ( ๐‘ฅ , ๐‘ฆ )

2 ๐‘ฅ + ๐‘ฆ 20 , ๐‘ฅ

0 , 1 , 2 , ย andย  ๐‘ฆ

0 , 1 , 2 f(x,y)= 20 2x+y โ€‹ ,x=0,1,2,ย andย y=0,1,2 (a) Find the joint cumulative distribution function (CDF) of ๐‘‹ X and ๐‘Œ Y.

(b) Determine if ๐‘‹ X and ๐‘Œ Y are independent.

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Solution

(a) The joint cumulative distribution function (CDF) of X and Y is obtained by integrating the joint density function over the range of the variables. The CDF, F(x,y), is given by:

F(x,y) = โˆซโˆซf(u,v) du dv, where the double integral is over the region 0 โ‰ค u โ‰ค x and 0 โ‰ค v โ‰ค y.

So, we have:

F(x,y) = โˆซ (from 0 to x) โˆซ (from 0 to y) (2u + v)/20 du dv = โˆซ (from 0 to x) [(u^2 + uv)/20] (from 0 to y) du = โˆซ (from 0 to x) [y^2/20 + xy/20] du = [(x^2y/20 + xy^2/40)] (from 0 to x) = x^2y/20 + xy^2/40

(b) X and Y are independent if and only if the joint density function f(x,y) can be written as the product of the marginal density functions of X and Y.

The marginal density functions are obtained by integrating the joint density function over the range of the other variable.

For X, we have:

f_X(x) = โˆซ (from 0 to 2) f(x,y) dy = โˆซ (from 0 to 2) (2x + y)/20 dy = [2xy/20 + y^2/40] (from 0 to 2) = 2x/10 + 1/5 = x/5 + 1/5

For Y, we have:

f_Y(y) = โˆซ (from 0 to 2) f(x,y) dx = โˆซ (from 0 to 2) (2x + y)/20 dx = [x^2/20 + xy/20] (from 0 to 2) = 2/20 + y/10 = 1/10 + y/10

The product of the marginal densities is:

f_X(x) * f_Y(y) = (x/5 + 1/5) * (1/10 + y/10) = x/50 + y/50 + x*y/50 + y/100

This is not equal to the joint density function f(x,y) = (2x + y)/20, so X and Y are not independent.

This problem has been solved

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