A 1.0 m long metallic rod is rotated frequency of 400 rad/s about an axis normal to the rod passing through its one end. The other end of the rod is in contact with the circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis everywhere. Calculate the emf developed between the centre and the ring
Question
A 1.0 m long metallic rod is rotated frequency of 400 rad/s about an axis normal to the rod passing through its one end. The other end of the rod is in contact with the circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis everywhere. Calculate the emf developed between the centre and the ring
Solution 1
The emf developed in a rotating rod in a magnetic field is given by the equation:
emf = 0.5 * B * L^2 * ω
where: B is the magnetic field strength, L is the length of the rod, ω is the angular velocity.
Substituting the given values into the equation:
emf = 0.5 * 0.5 T * (1.0 m)^2 * 400 rad/s emf = 0.5 * 0.5 T * 1.0 m^2 * 400 rad/s emf = 50 V
So, the emf developed between the center and the ring is 50 Volts.
Solution 2
The emf developed in a rotating rod in a magnetic field is given by the equation:
emf = 0.5 * B * L^2 * ω
where: B is the magnetic field strength, L is the length of the rod, ω is the angular velocity.
Substituting the given values into the equation:
emf = 0.5 * 0.5 T * (1.0 m)^2 * 400 rad/s emf = 0.5 * 0.5 T * 1.0 m^2 * 400 rad/s emf = 50 V
So, the emf developed between the center and the ring is 50 Volts.
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