Current in a single loop circuit containing a single resistance R and an EMF device with EMF E and internal resistance r isa.i=R/(E+r)b.i=E/(R+r)c.i=E/Rrd.i=2E/(R+r)

A steady current is passing through a coil, magnitude of self- induced emf in it,will be:A. zero ⃝ B. maximum ⃝C.  = LIt ⃝ D.  =  ILt

For physics lab, two students constructed an RL circuit similar to the one shown in the figure, with = 6.00 V, L = 7.00 mH, and R = 5.80 Ω.A rectangular circuit contains a battery of emf ℰ on its left side, with the positive terminal above the negative terminal. An open switch S is on the top side, an inductor L is on the right side, and a resistor R is on the bottom side.(a)What is the inductive time constant of the circuit (in ms)? ms(b)Calculate the current in the circuit (in A) 250 µs after the switch is closed. A(c)What is the value of the final steady-state current (in A)? A(d)After what time interval (in ms) does the current reach 80.0% of its maximum value?

A resistor is connected across an oscillating emf with a peak current through the resistor of 1.50 A. If the resistance R is tripled, what is the peak current? 0.500 A 0.866 A 1.50 A 4.50 A

A 10 V cell of negligible internal resistance is connected in parallel across a battery of emf 200 V and internal resistance 38 Ω as shown in the figure. Find the value of current in the circuit.

If i is current through the circuit and E is EMF of battery then power P at which chemical energy of battery is dissipated isa.P=E/i