Oxygen and water are produced when hydrogen peroxide breaks down. The chemical term for this process is decomposition. The decomposition of H2O2 happens naturally at a slow rate, as shown in the equation below:2H2O2 (aq) → 2H2O (l) + O2 (g)Outline how you would test that oxygen was produced.
Question
Oxygen and water are produced when hydrogen peroxide breaks down. The chemical term for this process is decomposition. The decomposition of H2O2 happens naturally at a slow rate, as shown in the equation below:2H2O2 (aq) → 2H2O (l) + O2 (g)Outline how you would test that oxygen was produced.
Solution 1
To test that oxygen was produced in the decomposition of hydrogen peroxide, you could follow these steps:
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Set up your experiment: You will need a container of hydrogen peroxide, a catalyst to speed up the reaction (such as yeast or potassium iodide), a test tube to capture the gas produced, and a glowing splint.
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Add the catalyst to the hydrogen peroxide: This will start the decomposition reaction. Oxygen and water will start to form.
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Capture the gas: As the reaction proceeds, gas will be produced. You can capture this gas by placing the test tube over the mouth of the container.
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Test the gas: Once you have captured some of the gas, remove the test tube from the container. Immediately place a glowing splint into the test tube. If the splint re-ignites or burns more brightly, this is a positive test for oxygen.
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Record your observations: Make sure to note down what you observe during the experiment. This will be important for your conclusions.
Remember to always follow safety guidelines when conducting experiments.
Solution 2
To test that oxygen was produced in the decomposition of hydrogen peroxide, you could follow these steps:
-
Set up your experiment: You will need a container of hydrogen peroxide, a catalyst to speed up the reaction (such as yeast or potassium iodide), a test tube to capture the gas produced, and a glowing splint.
-
Add the catalyst to the hydrogen peroxide: This will start the decomposition reaction. Oxygen and water will start to form.
-
Capture the gas: As the reaction proceeds, gas will be produced. You can capture this gas by placing the test tube over the mouth of the container.
-
Test the gas: Once you have captured some of the gas, remove the test tube from the container. Immediately place a glowing splint into the test tube. If the splint re-ignites or burns more brightly, this is a positive test for oxygen.
-
Record your observations: Make sure to note down what you observe during the experiment. This will be important for your conclusions.
Remember to always follow safety guidelines when conducting experiments.
Similar Questions
*19* Turn over ► IB/M/Jun23/8464/C/2H Do not write outside the box 0 6 . 1 The equation for the decomposition of hydrogen peroxide is: 2 H2O2 → 2 H2O + O2 Describe a test to identify the gas produced in the reaction. [2 marks] Test Result
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The equation for the decomposition of hydrogen peroxide is shown.2H_{2}*O_{2}(aq) -> 2H_{2}*O(l) + O_{2}(g) 25.0 cm³ of aqueous hydrogen peroxide forms 48.0 cm³ of oxygen at room temperature and pressure (r.t.p.).Calculate the concentration of aqueous hydrogen peroxide at the start of the experiment using the following steps.Calculate the number of moles of oxygen formed.molDeduce the number of moles of hydrogen peroxide that decomposed.molCalculate the concentration of hydrogen peroxide in mol / d * m ^ 3mol / d * m ^ 3[3]Calculate the volume of O, gas, at room temperature and pressure ( r .t.p.) needed to produce 1260 g of HNO3. Use the following steps.4.The equation for the reaction in stage 3 is shown.4N*O_{2} + 2H_{2}*O + O_{2} -> 4HNO
A student investigated the rate of decomposition of hydrogen peroxide using three different catalysts: • manganese dioxide • copper oxide • zinc oxide. Figure 2 shows the apparatus. Figure 2 This is the method used. 1. Measure 20 cm 3of hydrogen peroxide solution into a flask. 2. Add 0.5 g of manganese dioxide catalyst to the flask. 3. Attach a gas syringe to the flask. 4. Measure the volume of oxygen produced every 30 seconds for 180 seconds. 5. Repeat steps 1 to 4 two more times. 6. Repeat steps 1 to 5 using copper oxide catalyst. 7. Repeat steps 1 to 5 using zinc oxide catalyst. it speeds the reaction19 *19* Turn over ► IB/M/Jun23/8464/C/2H Do not write outside the box 0 6 . 1 The equation for the decomposition of hydrogen peroxide is: 2 H2O2 → 2 H2O + O2 Describe a test to identify the gas produced in the reaction. [2 marks] Test Result 0 6 . 2 Using 10 cm 3of hydrogen peroxide solution gives less accurate results than using 20 cm 3of hydrogen peroxide solution of the same concentration. Explain why. [2 marks] 0 6 . 3 Suggest one possible source of systematic error in the investigation. [1 mark] Question 6 continues on the next page relighting a slint. Place a glowing splint into a test tube containing the gas. if the splint relights oxygen is presentbecause 10cm^3 of the peroxide solution would be a limiting factor as it does not fullyreact with the catalyst20cm^3 is less dilute than 10cm^3 so there is more consitant results as if you measure 9cm^3 instead of 10cm^3 you have reduced the volume by 10% whereas if you measure 19cm^3 instead of20cm^3 you have only reduced the bolume by 5%? so it leads to more accurate resultsmeasuring the catalyst on a balance scale with a zero error20 *20* IB/M/Jun23/8464/C/2H Do not write outside the box Table 3 shows the results for manganese dioxide catalyst. Table 3 Time in seconds 0 30 60 90 120 150 180 Volume of gas in cm 30 22 38 41 54 58 60 Figure 3 shows a graph of the results with copper oxide catalyst and with zinc oxide catalyst. Figure 3 0 6 . 4 Complete Figure 3. You should: • plot the data from Table 3 • draw a line of best fit. The first point has been plotted for you. [3 marks] it says line of best fit so does that mean it wouldnt be a curve (like the blue line?)21 *21* Turn over ► IB/M/Jun23/8464/C/2H Do not write outside the box 0 6 . 5 Which catalyst gives the fastest rate of reaction? Give one reason for your answer. Use the completed Figure 3. [2 marks] Catalyst Reason 0 6 . 6 The rate of reaction is not dependent on the volume of hydrogen peroxide solution. Explain why.
What is the oxidation state of oxygen in peroxides?
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