[20 points] Consider an economy with 3 goods and 30 agents. There are 10 agents each with the utility functionu(x 1 ,x 2 ,x 3 )=lnx 1 +2lnx 2 +3lnx 3 and endowmentse 1 =(3,2,1). Also, the other 20 agents each have the utility functionu(z 1 ,z 2 ,z 3 )=3lnz 1 +2lnz 2 +lnz 3 and endowmentse 2 =(1,2,3). Normalizep 3 =1. (a) Derive all 3 market-clearing conditions. (b) Calculate the Walrasian equilibrium pricesp 1∗ andp 2∗ . [Hint: One may use any 2 of the 3 market-clearing conditions to solve for these 2 prices.]
Question
[20 points] Consider an economy with 3 goods and 30 agents. There are 10 agents each with the utility functionu(x 1 ,x 2 ,x 3 )=lnx 1 +2lnx 2 +3lnx 3 and endowmentse 1 =(3,2,1). Also, the other 20 agents each have the utility functionu(z 1 ,z 2 ,z 3 )=3lnz 1 +2lnz 2 +lnz 3 and endowmentse 2 =(1,2,3). Normalizep 3 =1. (a) Derive all 3 market-clearing conditions. (b) Calculate the Walrasian equilibrium pricesp 1∗ andp 2∗ . [Hint: One may use any 2 of the 3 market-clearing conditions to solve for these 2 prices.]
Solution
This is a problem of general equilibrium in an economy with three goods and two types of agents.
(a) The market-clearing conditions are derived from the fact that the total supply of each good must equal the total demand for each good.
For good 1, the total supply is 103 + 201 = 50, and the total demand is 10x1 + 20z1. So the market-clearing condition for good 1 is 10x1 + 20z1 = 50.
For good 2, the total supply is 102 + 202 = 60, and the total demand is 10x2 + 20z2. So the market-clearing condition for good 2 is 10x2 + 20z2 = 60.
For good 3, the total supply is 101 + 203 = 70, and the total demand is 10x3 + 20z3. So the market-clearing condition for good 3 is 10x3 + 20z3 = 70.
(b) To calculate the Walrasian equilibrium prices p1* and p2*, we can use any two of the three market-clearing conditions.
Let's use the conditions for goods 1 and 2.
From the utility functions, we know that the marginal rate of substitution (MRS) between any two goods is equal to the ratio of their prices.
For the first type of agents, MRS12 = (2/1)(p1/p2) and MRS13 = (3/1)(p1/p3).
For the second type of agents, MRS21 = (2/3)(p2/p1) and MRS23 = (1/3)(p2/p3).
Setting these equal to each other and solving for p1 and p2, we get p1* = 2/3 and p2* = 1/3.
Please note that this is a simplified solution and the actual calculation may involve more steps and algebraic manipulations.
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