Find the value of ds/du at u = 2 if s = t^2 + 5t and t = (u^2 + 2u)^1/3 .

Find the value of the expressiont ÷ 2 ÷ (–1)v ÷ sufor s = –2, t = –16, u = 3, and v = 3.

Determine the Laplace transform ofg(t)=5sin(8t)u5(t)

Find x5 − 5x2 dx.SOLUTION Let u = 5 − 5x2. Then du = dx, so x dx = du andx5 − 5x2 dx =  · 1u du =  · u−1/2 du =  2u + C =  + C  (in terms of x).

z = 9u find dz/du and dz/dv u 2 + 5v

a(t) = 2t + 5,    s(0) = 7,    v(0) = −9