Graph the feasible region for the system of inequalities.2x + y ≤ 4x - 1 ≥ 0
Question
Graph the feasible region for the system of inequalities.2x + y ≤ 4x - 1 ≥ 0
Solution
Sure, here are the steps to graph the feasible region for the system of inequalities:
Step 1: Understand the inequalities The system of inequalities is: 2x + y ≤ 4 x - 1 ≥ 0
Step 2: Rearrange the inequalities The inequalities can be rearranged as: y ≤ -2x + 4 x ≥ 1
Step 3: Graph the inequalities Start by drawing a graph with x and y axes.
For the first inequality y ≤ -2x + 4:
- Draw a line for y = -2x + 4. This line will intersect the y-axis at (0,4) and the x-axis at (2,0).
- Since the inequality is 'less than or equal to', the area below the line is shaded.
For the second inequality x ≥ 1:
- Draw a vertical line at x = 1.
- Since the inequality is 'greater than or equal to', the area to the right of the line is shaded.
Step 4: Identify the feasible region The feasible region is the area where the shaded regions for both inequalities overlap. This is the region that satisfies both inequalities.
Remember, the lines for the inequalities are also part of the feasible region because the inequalities are 'less than or equal to' and 'greater than or equal to', not 'less than' and 'greater than'.
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