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A student dissolved 5 g of sugar in 100 mL of distilled water in beaker A. She dissolved100 g of sugar in100 mL of distilled water in beaker B. Then she dropped a few raisins ofequal weight in each beaker. After two hours she found the raisins in A swollen and thosein B shrunken. The inference drawn is thata) sugar concentration of raisins is lower than that of solution A and higher than thatof solution B.b) sugar concentration of raisins is higher than that of solution A and lower than thatof solution B.c) in B the cell membrane of raisins was damaged.d) in A the permeability of the cell membrane of raisins to water was enhanced

Question

A student dissolved 5 g of sugar in 100 mL of distilled water in beaker A. She dissolved100 g of sugar in100 mL of distilled water in beaker B. Then she dropped a few raisins ofequal weight in each beaker. After two hours she found the raisins in A swollen and thosein B shrunken. The inference drawn is thata) sugar concentration of raisins is lower than that of solution A and higher than thatof solution B.b) sugar concentration of raisins is higher than that of solution A and lower than thatof solution B.c) in B the cell membrane of raisins was damaged.d) in A the permeability of the cell membrane of raisins to water was enhanced

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Solution

The correct answer is:

b) sugar concentration of raisins is higher than that of solution A and lower than that of solution B.

Explanation:

This is a demonstration of osmosis, the process by which water moves from an area of lower solute concentration to an area of higher solute concentration across a semi-permeable membrane.

In beaker A, the sugar concentration in the solution is lower than in the raisins. Therefore, water moves from the solution into the raisins, causing them to swell.

In beaker B, the sugar concentration in the solution is higher than in the raisins. Therefore, water moves from the raisins into the solution, causing the raisins to shrink.

This shows that the sugar concentration of the raisins is higher than that of solution A and lower than that of solution B.

This problem has been solved

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