To find A(2), we need to evaluate the integral from 2 to 2. However, the integral over an interval where the upper and lower limits are the same is always 0. So, A(2) = 0.

To find A'(3), we use the Fundamental Theorem of Calculus, which states that if a function f is defined by an integral, then the derivative of f is the original function in the integral. So, A'(x) = x^2 - 9^3. Substituting x = 3, we get A'(3) = 3^2 - 9^3 = 9 - 729 = -720.

Question

To find A(2), we need to evaluate the integral from 2 to 2. However, the integral over an interval where the upper and lower limits are the same is always 0. So, A(2) = 0.

To find A'(3), we use the Fundamental Theorem of Calculus, which states that if a function f is defined by an integral, then the derivative of f is the original function in the integral. So, A'(x) = x^2 - 9^3. Substituting x = 3, we get A'(3) = 3^2 - 9^3 = 9 - 729 = -720.

Knowee AI · Accepted Answer

To find A(2), we need to evaluate the integral from 2 to 2. However, the integral over an interval where the upper and lower limits are the same is always 0. So, A(2) = 0.

To find A'(3), we use the Fundamental Theorem of Calculus, which states that if a function f is defined by an integral, then the derivative of f is the original function in the integral. So, A'(x) = x^2 - 9^3. Substituting x = 3, we get A'(3) = 3^2 - 9^3 = 9 - 729 = -720.

he function A is deﬁned for x ≥ 2 by A(x) =∫ x2(t2 − 9)3 dt. [5 marks]Determine A(2) and A′(3)

Question

Solution

Similar Questions

Upgrade your grade with Knowee