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Anshul moves towards East a distance of 5 m, then he turns to his left and walks 20 metres, then againhe turns left and walks 15 meters. Now he turns 45° towards his right and goes straight to cover20 2 m meters. How far is he from his starting point ?(1) 40 m (2) 30 m(3) 50 m (4) 55 m

Question

Anshul moves towards East a distance of 5 m, then he turns to his left and walks 20 metres, then againhe turns left and walks 15 meters. Now he turns 45° towards his right and goes straight to cover20 2 m meters. How far is he from his starting point ?(1) 40 m (2) 30 m(3) 50 m (4) 55 m

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Solution

To solve this problem, we can break it down into steps:

  1. Anshul starts at a point and moves 5m East.
  2. He then turns left (which would be North if we consider the standard directions) and moves 20m.
  3. He turns left again (which would now be West) and moves 15m. At this point, he is 5m West of his starting point (since he moved 15m West after moving 20m North).
  4. He then turns 45° to his right. This direction is between North and East. He then moves 20√2m.

The problem is asking for the straight-line distance (as the crow flies) from his starting point to his ending point. This forms a right triangle where the horizontal distance is 5m (West of the starting point) and the vertical distance is 20m (North of the starting point).

We can use the Pythagorean theorem to solve for the hypotenuse of this triangle, which represents the straight-line distance from the starting point to the ending point. The Pythagorean theorem is a^2 + b^2 = c^2, where a and b are the lengths of the legs of the right triangle and c is the length of the hypotenuse.

So, the distance would be √((5)^2 + (20)^2) = √(25 + 400) = √425 = approximately 20.6m.

Therefore, none of the given options (1) 40m, (2) 30m, (3) 50m, (4) 55m are correct. The distance should be approximately 20.6m.

This problem has been solved

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