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Multi Choice Type QuestionIn the expression x = y + x, where y is a floating-point variable and x is an integer variable. What happens if we print x as an integer?Marks : 1Negative Marks : 0Answer hereConverts y to an integer typeExplicitly converts x to a floating-point typeConverts y to an integer type and also explicitly converts x to a floating-point typeNone of the mentioned options

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Multi Choice Type QuestionIn the expression x = y + x, where y is a floating-point variable and x is an integer variable. What happens if we print x as an integer?Marks : 1Negative Marks : 0Answer hereConverts y to an integer typeExplicitly converts x to a floating-point typeConverts y to an integer type and also explicitly converts x to a floating-point typeNone of the mentioned options

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The answer is "Converts y to an integer type". In the expression x = y + x, where y is a floating-point variable and x is an integer variable, if we print x as an integer, the floating-point variable y is implicitly converted to an integer type. This is because in mixed-type expressions, the type with less precision (integer in this case) is converted to the type with more precision (floating-point in this case) before the operation is performed. However, since the result is being assigned to an integer variable x, the final result is converted back to an integer.

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